std::alignment_of
From cppreference.com
Defined in header <type_traits>
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template< class T > struct alignment_of; |
(since C++11) | |
Provides the member constant value equal to the alignment requirement of the type T, as if obtained by an alignof expression. If T is an array type, returns the alignment requirements of the element type.
Contents |
Inherited from std::integral_constant
Member constants
value [static] |
alignof(typename std::remove_all_extents<T>::type) (public static member constant) |
Member functions
operator std::size_t |
converts the object to std::size_t, returns value (public member function) |
Member types
Type | Definition |
value_type | std::size_t |
type | std::integral_constant<std::size_t, value> |
[edit] Possible implementation
template< class T > struct alignment_of : std::integral_constant< std::size_t, alignof(typename std::remove_all_extents<T>::type) > {}; |
[edit] Example
#include <iostream> #include <type_traits> class A {}; int main() { std::cout << std::alignment_of<A>::value << '\n'; std::cout << std::alignment_of<int>::value << '\n'; std::cout << std::alignment_of<double>::value << '\n'; }
Output:
1 4 8
[edit] See also
alignof operator | queries alignment requirements of a type (since C++11) |
(C++11) |
defines the type suitable for use as uninitialized storage for types of given size (class template) |
(C++11) |
defines the type suitable for use as uninitialized storage for all given types (class template) |
(C++11) |
POD type with alignment requirement as great as any other scalar type (typedef) |