std::alignment_of
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header <type_traits>
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|   template< class T > struct alignment_of;  | 
(since C++11) | |
Provides the member constant value equal to the alignment requirement of the type T, as if obtained by an alignof expression. If T is an array type, returns the alignment requirements of the element type.
Contents | 
Inherited from std::integral_constant
Member constants
|    value [static]  | 
   alignof(typename std::remove_all_extents<T>::type)    (public static member constant)  | 
Member functions
|    operator std::size_t  | 
   converts the object to std::size_t, returns value   (public member function)  | 
Member types
| Type | Definition | 
| value_type | std::size_t | 
| type | std::integral_constant<std::size_t, value> | 
[edit] Possible implementation
template< class T > struct alignment_of : std::integral_constant< std::size_t, alignof(typename std::remove_all_extents<T>::type) > {};  | 
[edit] Example
#include <iostream> #include <type_traits> class A {}; int main() { std::cout << std::alignment_of<A>::value << '\n'; std::cout << std::alignment_of<int>::value << '\n'; std::cout << std::alignment_of<double>::value << '\n'; }
Output:
1 4 8
[edit] See also
| alignof operator | queries alignment requirements of a type (since C++11) | 
|    (C++11)  | 
   defines the type suitable for use as uninitialized storage for types of given size   (class template)  | 
|    (C++11)  | 
   defines the type suitable for use as uninitialized storage for all given types   (class template)  | 
|    (C++11)  | 
   POD type with alignment requirement as great as any other scalar type   (typedef)  |